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4x^2-30x-255=0
a = 4; b = -30; c = -255;
Δ = b2-4ac
Δ = -302-4·4·(-255)
Δ = 4980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4980}=\sqrt{4*1245}=\sqrt{4}*\sqrt{1245}=2\sqrt{1245}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{1245}}{2*4}=\frac{30-2\sqrt{1245}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{1245}}{2*4}=\frac{30+2\sqrt{1245}}{8} $
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